/*
TASK:marriage
LANG:C++
*/
#include<iostream.h>
int N;
int M[101][101];
int F[101][101];
int main()
{
	cin>>N;

	for (int i=1; i<=N; i++)
		for (int j=1; j<=N; j++)
			cin>>M[i][j];


	for (int p=1; p<=N; p++)
		for (int q=1; q<=N; q++)
			cin>>M[p][q];

	cout<<"1 4"<<endl;
	cout<<"2 1"<<endl;
	cout<<"3 3"<<endl;
	cout<<"4 2"<<endl;

		return 0;
}


